Question

Find the equation of a line given the point and slope below. Arrange your answer in the form y = mx + b, where b is the constant.

(7, 1)
m = 10
Can someone help me and show me how to do these

Answer 1

Answer:

Step-by-step explanation:

an equation is :  y = 10x+b

calculate b : this line passes by : (7;1) when x =7  y = 1

so : 10(7)+ b=1

b= -69

so : y = 10x-69

Answer 2

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

$y = mx+b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

How do we have to:

$m = 10\\(x, y) :( 7,1)$

So, the equation is of the form:

$y = 10x+b$

We substitute the point and find b:

$1 = 10 (7)+b\\1 = 70+b\\b = 1-70\\b = -69$

Finally, the equation is of the form:

$y = 10x-69$

Answer:

$y = 10x-69$