Answer:
Step-by-step explanation:
we have given F(s)=[tex]\frac{11}{\left ( s^2+9 \right )^2}[/tex]
[tex]\frac{11}{\left ( s^2+9 \right )^2}[/tex] = [tex]\frac{A}{S^2+9}+\frac{B}{\left ( S^2+9 \right )^2}[/tex]
using partial fraction method
11= A[tex]S^2[/tex]+9A+B
on comparing A=0 and B=11
putting the value of A and B in function
F(s)=[tex]\frac{11}{\left ( s^2+9 \right )^2}[/tex]
now taking inverse laplace
f(t)=[tex]11te^{-9t}[/tex]
