Answer:
State A had approximately 3,362 more earthquakes than State B
Step-by-step explanation:
Let
x-----> the number of earthquakes during a given time span
y ----> the land area affected
z----> seismic activity density of a region
step 1
Find the number of earthquakes during a given time span of State A
we know that
[tex]z=\frac{x}{y}[/tex]
we have
[tex]z=0.0299\\ y=163,696\ mi^{2}[/tex]
substitute and solve for x
[tex]0.0299=\frac{x}{163,696}\\ x=0.0299*(163,696)=4,895\ earthquakes[/tex]
step 2
Find the number of earthquakes during a given time span of State B
we know that
[tex]z=\frac{x}{y}[/tex]
we have
[tex]z=0.1402\\ y=10,931\ mi^{2}[/tex]
substitute and solve for x
[tex]0.1402=\frac{x}{10,931}\\ x=0.1402*(10,931)=1,533\ earthquakes[/tex]
step 3
Compare the number of earthquakes both states
state A ----> [tex]4,895\ earthquakes[/tex]
state B ----> [tex]1,533\ earthquakes[/tex]
Find the difference
[tex]4,895-1,533=3,362\ earthquakes[/tex]
therefore
State A had approximately 3,362 more earthquakes than State B
