Answer:
The required number of years are 7.52 years.
Step-by-step explanation:
Given : $10000 is deposited in an account earning 4% interest compounded continuously.
To find : How long it takes for the amount in the account to double?
Solution :
Applying Continuous interest formula,
[tex]A=Pe^{rt}[/tex]
Where, P is the principal P=$10000
r is the interest rate r=4%=0.04
t is the time
We have given, Amount in the account to double
i.e. A=2P
Substitute the value in the formula,
[tex]2P=Pe^{rt}[/tex]
[tex]2=e^{0.04t}[/tex]
Taking log both side,
[tex]\log 2=\log (e^{0.04t})[/tex]
[tex]\log 2=0.04t\times log e[/tex]
[tex]t=\frac{\log 2}{0.04}[/tex]
[tex]t=7.52[/tex]
Therefore, The required number of years are 7.52 years.