Answer: [tex]3\Omega[/tex]
Explanation:
When devices [tex]n[/tex] are connected in parallel, the total resistance [tex]R[/tex] is calculated by:
[tex]\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+...+\frac{1}{R_{n}}[/tex]
In this case we have 2 devices connected in parallel, and their resistances are
[tex]R_{1}=12\Omega[/tex] and [tex]R_{2}=4\Omega[/tex]. Therefore:
[tex]\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}[/tex]
[tex]\frac{1}{R}=\frac{1}{12\Omega}+\frac{1}{4\Omega}[/tex]
[tex]\frac{1}{R}=\frac{1}{3\Omega}[/tex]
Finally:
[tex]R=3\Omega[/tex] This is the total resistance of the two devices