Respuesta :

Answer:

Part 1) The algebraic expression is equal to [tex]1.10(n-1)[/tex]  or [tex]1.10n-1.10[/tex]

Part 2) The algebraic expression is equal to [tex]\frac{1.10}{n}[/tex]

Step-by-step explanation:

Part 1) Algebraic expression of (n-1) increased by 110%

we know that

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

[tex]1.10(n-1)[/tex]

Distributed

[tex]1.10n-1.10[/tex]

Part 2) Algebraic expression of n^(-1) increased by 110%

we know that

110%=110/100=1.10

so

The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)

Remember that

[tex]n^{-1}=\frac{1}{n}[/tex]

so

[tex]1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}[/tex]

The algebraic expression is 2.1n - 2.1

The expression is given as:

n - 1

When it increases by 110%, the expression becomes

(n - 1) * (1 + 110%)

Express as decimal

(n - 1) * (1 + 1.10)

Evaluate the sum

(n - 1) * 2.10

Expand

2.1n - 2.1

Hence, the algebraic expression is 2.1n - 2.1

Read more about expressions at:

https://brainly.com/question/4344214

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