Question

Translate to an algebraic expression n−1 increased by 110%

Answer 1

Answer:

Part 1) The algebraic expression is equal to $1.10(n-1)$  or $1.10n-1.10$

Part 2) The algebraic expression is equal to $\frac{1.10}{n}$

Step-by-step explanation:

Part 1) Algebraic expression of (n-1) increased by 110%

we know that

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

$1.10(n-1)$

Distributed

$1.10n-1.10$

Part 2) Algebraic expression of n^(-1) increased by 110%

we know that

110%=110/100=1.10

so

The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)

Remember that

$n^{-1}=\frac{1}{n}$

so

$1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}$

Answer 2

The algebraic expression is 2.1n - 2.1

The expression is given as:

n - 1

When it increases by 110%, the expression becomes

(n - 1) * (1 + 110%)

Express as decimal

(n - 1) * (1 + 1.10)

Evaluate the sum

(n - 1) * 2.10

Expand

2.1n - 2.1

Hence, the algebraic expression is 2.1n - 2.1

Read more about expressions at:

https://brainly.com/question/4344214