a profectile is shot upward, and it's distance above the ground, in feet after s t seconds is represented by the function below. s(t)-4t^2+24t. use the number line to represent the interval on which the projectile is desce ding

the curve is representing the projectile. at t=0, the projectile is on the ground. at t=6, the projectile has finished its journey and is back on the ground. In between t=0 and t=6 will be the projectile's peak altitude. the point between t=0 and t=6 is t=3. So plug in t=3 and solve for s(t), and you get 36ft. gg

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a profectile is shot upward, and it's distance above the ground, in feet after s t seconds is represented by the function below. s(t)-4t^2+24t. use the number line to represent the interval on which the projectile is desce ding​

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a profectile is shot upward, and it's distance above the ground, in feet after s t seconds is represented by the function below. s(t)-4t^2+24t. use the number line to represent the interval on which the projectile is desce ding