Answer:
(a) 24.8 m/[tex]src^2[/tex]
Explanation:
acceleration due to gravity is given by [tex]g=\frac{GM}{R^2}=9.8 m/sec^2[/tex]
where G is gravitational constant M is mass of earth and R is radius of earth
it is given that mass of Jupiter is =318 M
and radius of earth =11.2 R
[tex]g_{jupiter}=\frac{318GM}{11.2^2\times R^2}=2.535\times 9.8=24.84375 m/sec^2[/tex]
so the acceleration due to gravity at Jupiter is 24.8 m/[tex]sec^2[/tex] so option a will be correct answer