Question

What is the value of x?

Answer 1

Answer:

a^2+b^2=c^2

30^2+16^2=c^2

900+256=c^2

1156=c^2

sq rt of 1156= sq rt of c^2

34=c

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Answer 2

To solve this you must use Pythagorean theorem:

$a^{2} +b^{2} =c^{2}$

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 16

b = 30

c = x

^^^Plug these numbers into the theorem

$16^{2} +30^{2} =x^{2}$

simplify

256 + 900 = $x^{2}$

1156 = $x^{2}$

To remove the square from x take the square root of both sides to get you...

34 = x  

Hope this helped!

~Just a girl in love with Shawn Mendes