Question

Simplify each expression. 3a^2b^-4/12a^-2b-2
A. a^4/4b^2
B.1/4b^6
C.1/4a^-4b^2
D.a^4/4b^6

Second question is
v^3w^-3/-v^-6w^3
A.-1/-v^3
B.-v^9/-w^6
C.1/v^3
-v^9w^-6
I NEED IMMEDIATELY!! PLEASE HELP THANK YOU VERY MUUUCH

Answer 1

Answer:

1) A. a^4/4b^2

2) -v^9w^-6

Step-by-step explanation:

1)

given

3a^2b^-4/12a^-2b-2

$\frac{3a^2b^{-4}}{12a^{-2}b^{-2}}$

canceling common factor 3, we get

$\frac{a^2b^{-4}}{4a^{-2}b^{-2}}$

$=\frac{b^{-4}a^{2-\left(-2\right)}}{4b^{-2}}$$=\frac{b^{-4}a^{2-\left(-2\right)}}{4b^{-2}}$

$=\frac{a^4}{4b^{-2-\left(-4\right)}}$

$=\frac{a^4}{4b^2}$

2)

Given:

v^3w^-3/-v^-6w^3

$=-\frac{v^3w^{-3}}{v^{-6}w^3}\\=\frac{w^{-3}v^{3-\left(-6\right)}}{w^3}\\=\frac{v^9w^{-3}}{w^3}\\=\frac{v^9}{w^{3-\left(-3\right)}}\\=-\frac{v^9}{w^6}$

=-v^9w^-6 !

Answer 2

Answer:

IT'S A THEN B

Step-by-step explanation: