Question

What is the diameter of the circle whose center is at (6, 0) and that passes through the point (2, -3)?
A. 10
B. 12
C. 11
D. 5

Answer 1

Answer:

Option A $D=10\ units$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center of the circle and any point on the circle is equal to the radius.

we have

(6,0) and (2,-3)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute

$r=\sqrt{(-3-0)^{2}+(2-6)^{2}}$

$r=\sqrt{(-3)^{2}+(-4)^{2}}$

$r=\sqrt{25}$

$r=5\ units$

step 2

Find the diameter

we know that

The diameter is two times the radius

so

$D=(2)5=10\ units$