Question

What is the equation of the line that contains the point (-5, -1) and has a slope of 4? Write in slope-intercept form.
A y = 4x - 19
B.y = 4x+19
C y = 4x-1
D. y = 4x+1

Answer 1

$\huge{\boxed{\text{B.}\ y=4x+19}}$

Point-slope form is $y-y_1=m(x-x_1)$, where $m$ is the slope and $(x_1, y_1)$ is a point on the line.

Substitute the values. $y-(-1)=4(x-(-5))$

Simplify the negative subtraction. $y+1=4(x+5)$

Distribute the $4$. $y+1=4x+20$

Subtract $1$ on both sides. $\boxed{y=4x+19}$

Answer 2

Answer:

B.y = 4x+19

Step-by-step explanation:

We are given a point and a slope, we can write the equation in point slope form

y-y1 = m (x-x1)

y--1 = 4(x--5)

y+1 = 4(x+5)

We want the equation in slope intercept form(y=mx+b)

Distribute

y+1 =4x+20

Subtract 1 from each side

y+1-1 = 4x+20-1

y = 4x+19