Question

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 7 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.

Answer 1

Answer: 0.3929

Step-by-step explanation:

Given : The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 7 minutes.

The probability density function :-

$f(x)=\dfrac{1}{7-0}=\dfrac{1}{7}$

The interval of probability distribution of success event = [4.25,7] =$7-4.25=2.75$

Then , the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes is given by :-

$\dfrac{2.75}{7}=0.39285714\approx0.3929$