Answer:
The earthquake is 1390.4014 km far away.
Explanation:
Given:
Speed of transverse (S) waves, v₁ = 4.88 km/s
Speed of longitudinal(P) waves, v₂ = 7.94 km/s
Time difference between the P waves and the S waves, Δt = 1.83 min
Also, 1 minute = 60 seconds
So,
Δt = 1.83 min = 1.83×60 seconds = 109.8 seconds
Let the earthquake is d km far from the seismograph. So,
Distance = d
Time taken by transverse (S) waves:
t₁ = d / v₁ = d / 4.88 seconds
Time taken by longitudinal(P) waves, v₂:
t₂ = d / v₂ = d / 7.94 seconds
Time difference, Δt = t₁ - t₂ = (d / 4.88) - (d / 7.94)
109.8 = d (1/4.88 - 1/7.94)
109.8 = d (0.07897)
Solving for d,
d = 109.8 / 0.07897 = 1390.4014 km
Thus, The earthquake is 1390.4014 km far away.