Question

A bag contains 4 blue balls, 7 yellow balls and 4 white balls. Event A is defined as drawing a blue ball on the first draw and event B is defined as
drawing a white ball on the second draw. If two balls are drawn from the bag, one after the other and not replaced,
what is P(B|A) expressed in simplest form?

Answer 1

Answer:

Im srry that im late but: the answer is B) 1/5.

Answer 2

The probability P(B|A) expressed in simplest form is $\frac{4}{15}$.

What is probability?

The probability indicates the chance of happening of a particular event or incident.

The probability of drawing a blue ball on first draw is

$= P(A)\\= \frac{4}{15}$

The probability of drawing a white ball on second draw without replacing is

$= P(B)\\= \frac{4}{14}$

Therefore, the required probability

P(B|A)

= P(A∩B)/P(B)

P(A∩B)

$= (\frac{4}{15})(\frac{4}{14})$

Now,

P(B|A)

= P(A∩B)/P(B)

$= \frac{(\frac{4}{15})(\frac{4}{14})}{\frac{4}{14}} \\= (\frac{4}{15})$

Learn more about probability here: https://brainly.com/question/27981868

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