Respuesta :

r3t40

Points [tex]X(-2,1)[/tex] and [tex](-4,-3)[/tex] are defined therefore we have all data we need to construct equation.

Linear function has a form of,

[tex]y=ax+b[/tex]

First calculate the slope a.

[tex]a=\dfrac{dy}{dx}=\dfrac{-3-1}{-4-1}=\dfrac{-4}{-5}=\dfrac{4}{5}[/tex]

Now plug in the coordinates of either one of the points into the linear function. I'll pick point X.

[tex]y=ax+b\Longrightarrow1=\dfrac{4}{5}\cdot(-2)+b[/tex]

Now just solve for b.

[tex]1=-\dfrac{8}{5}+b\Longrightarrow b=\dfrac{13}{5}[/tex]

The equation is therefore,

[tex]\boxed{y=\dfrac{4}{5}x+\dfrac{13}{5}}[/tex]

Hope this helps.

r3t40

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