Question

A company is replacing cables with fiber optic lines in rectangular casing BCDE. If segment DE = 2.5 cm and segment BE = 3 cm, what is the smallest diameter of pipe that will fit the fiber optic line?

Answer 1

Answer:

The smaller diameter is $3.9\ cm$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The diameter of the circle is equal to BD

Applying the Pythagoras Theorem

$BD^{2} =BE^{2} +DE^{2}$

substitute the given values

$BD^{2} =3^{2} +2.5^{2}\\ BD^{2} =15.25\\ BD=3.9\ cm$

Answer 2

Answer:

3.9

Step-by-step explanation:

use Pythagorean Theorem

plus i took the test :)