Question

the point-slope form of the equation below that represents the line that passes through the points (−3, 2) and (2, 1).

Answer 1

Answer:

$\large\boxed{for\ (-3,\ 2):\ y-2=-\dfrac{1}{5}(x+3)}\\\boxed{for\ (2,\ 1):\ y-1=-\dfrac{1}{5}(x-2)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

========================================

We have the points (-3, 2) and (2, 1).

Substitute:

$m=\dfrac{1-2}{2-(-3)}=\dfrac{-1}{5}=-\dfrac{1}{5}$

for (-3, 2)

$y-2=-\dfrac{1}{5}(x-(-3))\\\\y-2=-\dfrac{1}{5}(x+3)$

for (2, 1)

$y-1=-\dfrac{1}{5}(x-2)$