Answer:
84=2l+2w
w=21
Step-by-step explanation:
84=2(l+w)
42=l+w
l=42-w
Area=l×w
A=(42-w)×w
Differentiate A=42w-w×w
with respective to "w".
dA/dw= 42-2w
For a minimum or maximum area
dA/dw=0
then, 42-2w=0
w=21
proving "A" is maximum when "w=21"
dA/dw>0 when w<21
dA/dw<0 when w>21
Therefore Area is maximum when "w=21"