Answer:
Part 1) The inequality that represent this situation is [tex]5(x+7)^{2} \geq1,050[/tex] or [tex]5x^{2}+70x+245 \geq1,050[/tex]
Part 2) Yes, 8 inches is a reasonable width for his tablet
Step-by-step explanation:
Part 1)
Let
L -----> the length of the screen television
W ----> the width of the screen television
x ----> the width of Andrew's tablet
we know that
[tex]L=5W[/tex] ------> equation A
[tex]W=x+7[/tex] ----> equation B
The area of the television is
[tex]A=LW[/tex] -----> equation C
Substitute equation A and equation B in equation C
[tex]A=5(x+7)(x+7)[/tex]
[tex]A=5(x+7)^{2}[/tex]
[tex]5(x+7)^{2} \geq1,050[/tex]
[tex]5(x^{2}+14x+49) \geq1,050[/tex]
[tex]5x^{2}+70x+245 \geq1,050[/tex] ------> inequality that represent this situation
Part 2) Determine if 8 inches is a reasonable width for his tablet
For x=8 in
Substitute in the inequality
[tex]5(8+7)^{2} \geq1,050[/tex]
[tex]5(15)^{2} \geq1,050[/tex]
[tex]1,125 \geq1,050[/tex] -----> is true
therefore
Yes, 8 inches is a reasonable width for his tablet