Question

High population density can cause increases in competition for resources, such as food and shelter. The table shows the number of zebras living in four different regions.


In which region is competition for resources most likely the greatest?

Region A

Region B

Region C

Region D

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Answer 1

Answer:

The answer is Region C

Step-by-step explanation:

Region C has total population of Zebra as 16,400 divided by the area occupied in square km which is 625. This gives population density of approximately 26 zebras/km square

$\frac{16400}{625} = 26.24$

If you follow the same procedure for other regions, you will discover that region C has the highest number of Zebras/square km which is 26.

I hope this helped?

Answer 2

The region that would have the greatest competition for resources is Region C.

What is population density?

Population density is the amount of organisms that live in a square feet of an area.

Population density = population / area

• Population density in Region A = 1312 / 212 = 6.19
• Population density in Region B = 630 / 314 = 2
• Population density in Region C = 16400 / 625 = 26.24
• Population density in Region D = 17800 / 902 = 19.7

To learn more about population density, please check:

https://brainly.com/question/3704320