Given that B, C, and D are the midpoints of ZYA, find the perimeter of ZYA.
A. 70.6
B. 72.6
C. 76.6
D. 77.6
![Given that B C and D are the midpoints of ZYA find the perimeter of ZYA A 706 B 726 C 766 D 776 class=](https://us-static.z-dn.net/files/ddf/666d753792c9af99a05ef6ad308c327b.png)
Answer:
D. 77.6
Step-by-step explanation:
We have been given a triangle ZYA in which B, C, and D are the midpoints. We are asked to find the perimeter of triangle ZYA.
We will triangle mid-segment theorem to solve our given problem.
The triangle mid-segment theorem states that the segment joining midpoints of two sides of a triangle is parallel to 3rd side and half the measure of parallel side.
[tex]\text{Measure of side YA}=2\times BD[/tex]
[tex]\text{Measure of side YA}=2\times 11.1[/tex]
[tex]\text{Measure of side YA}=22.2[/tex]
[tex]\text{Measure of side YZ}=2\times CD[/tex]
[tex]\text{Measure of side YZ}=2\times 13.7[/tex]
[tex]\text{Measure of side YZ}=27.4[/tex]
[tex]\text{Measure of side ZA}=2\times CB[/tex]
[tex]\text{Measure of side ZA}=2\times 14[/tex]
[tex]\text{Measure of side ZA}=28[/tex]
[tex]\text{Perimeter of triangle ZYA}=22.2+27.4+28[/tex]
[tex]\text{Perimeter of triangle ZYA}=77.6[/tex]
Therefore, the perimeter of triangle ZYA is 77.6 units.