Answer:
1039.23 m/s
Explanation:
Given:
Height, H = 3 x 10⁵m
acceleration of gravity on lo, a = 1.80 m/s² toward moon's surface i.e -1.80m/s² with respect to the earth
Now, at its highest point the velocity i.e the final velocity 'v' = 0m/s.
Now using the Newton's equation of motion
v² - u² =2as
where,
v = final velocity
u = initial velocity
a = acceleration
s = distance
now,
substituting the values we get
0²-u² = 2 × (-1.80) × 3 x 10⁵
or
[tex]u=\sqrt{10.8\times 10^5}=1039.23m/s[/tex]
Hence, the initial velocity with which the material is ejected is 1039.23 m/s