Answer:
280.3722 K,504.67°R ,7.222°C
Explanation:
FAHRENHEIT TO KELVIN: T(K)=(T(F°)+459.67)[tex]\frac{5}{9}[/tex]
we have to convert 45°F=(45+459.67)×[tex]\frac{5}{9}[/tex]
=280.3722
FAHRENHEIT TO RANKINE :T(R°)=T(F°)+459.67
we have to convert 45°F=45+459.67
=504.67
FAHRENHEIT TO CELSIUS:T(C°)=[tex]\frac{F-32}{9}[/tex]×5
we have to convert 45°F=[tex]\frac{45-32}{9}[/tex]×5
=7.22°C
