Answer:
τ ∝ [tex]\frac{1}{\omega .f}[/tex]
Explanation:
We know that Power, P = [tex]\frac{2\pi. N.T}{60}[/tex] -----(1)
where N is speed in rpm
T is torque
and
[tex]\tau =\frac{16.T}{\pi .D^{3}}[/tex] ---------(2)
where D is diameter
From (1) and (2) we get,
τ ∝ T
and T ∝ 1 / N
∴ τ ∝ 1 / N
Now we know, Angular velocity, ω = [tex]\frac{2\pi . N}{60}[/tex] -----(3)
and, ω = 2.π.f ---------------------------------(4)
where f is frequency
So from,(3) and (4), we get
ω ∝ N
and ω ∝ f
and since τ ∝ 1 / N
∴ τ ∝ 1 / ω
and τ ∝ 1 / f
Therefore, τ varies inversely to both ω and f