Respuesta :
Answer:
a) Maximum subnets=8
b) if there is no subnet , no. of hosts will be 32-2 = 30. If there are 8 subnets as above, then no. of hosts will b 4-2=2.
c) Valid subnets are 6
192.168.10.32
192.168.10.64
192.168.10.96
192.168.10.128
192.168.10.160
192.168.10.192
Explanation:
a) Maximum number of sub nets in the network
For number of sub nets in a network , which class this ip address belongs to
IP address 192.168.10.0
subnet mask 255.255.255.224
192 in ip address means it is a class C address.
In class C address -
Network address-24 bits
Host address-8bits
For number of subnets we check last block of subnet mask.
224 -covert this into binary
11100000
From binary form ,we can conclude that 3 bits are used for sub network as only 3 are 1.
=2^n
= 2^3 =8
b) Number of hosts
In a network,
Number of hosts is (2^host no -2)
We have subtracted 2 because out of these hosts two are used in broadcasting and other purposes.
Host number is equal to the 0's in the Subnet mask
255.255.255.224
convert this into binary number i.e
11111111.11111111.11111111.11100000
So,5 0's are there
Number of valid hosts= 2^5 -2
= 32-2
�� = 30
c) The Valid subnets are
For valid we have to perform Logical AND with IP Address and subnet mask.
IP address 192.168.10.0
subnet mask 255.255.255.224
Convert these in binary -
IP address 11000000.10101000.00001010.00000000
Subnet mask 11111111.11111111.11111111.11100000
after performing And operation- 11000000.10101000.00001010.00000000
192.168.10.0
this is the host address
192.168.10.224 this is the broadcast address
These are the valid sub nets
192.168.10.32
192.168.10.64
192.168.10.96
192.168.10.128
192.168.10.160
192.168.10.192
