Respuesta :
Answer:
Part A) [tex]\$42,888.48[/tex]
Part B) [tex]A=\$22,304[/tex]
Part C) The graph in the attached figure
Step-by-step explanation:
Part A) What will the account be worth in 20 years?
we know that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
[tex]t=20\ years\\ P=\$8,500\\ r=0.0812\\n=12[/tex]
substitute in the formula above
[tex]A=8,500(1+\frac{0.0812}{12})^{12*20}[/tex]
[tex]A=8,500(1.0068)^{240}[/tex]
[tex]A=\$42,888.48[/tex]
Part B) What if the deposit were compounded monthly with simple interest?
we know that
The simple interest formula is equal to
[tex]A=P(1+rt)[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest
t is Number of Time Periods
in this problem we have
[tex]t=20\ years\\ P=\$8,500\\r=0.0812[/tex]
substitute in the formula above
[tex]A=8,500(1+0.0812*20)[/tex]
[tex]A=\$22,304[/tex]
Part C) Could you see the situation in a graph? From what point one is better than the other?
Convert the equations in function notation
[tex]A(t)=8,500(1.0068)^{12t}[/tex] ------> equation A
[tex]A(t)=8,500(1+0.0812t)[/tex] -----> equation B
using a graphing tool
see the attached figure
Observing the graph, from the second year approximately the monthly compound interest is better than the simple interest.
![Ver imagen calculista](https://us-static.z-dn.net/files/dd5/7d7d42aca8ec3565f208e2dd49707e42.jpg)