Question

Determine the total energy E of water vapor with a mass of 2.50 kg, a specific internal energy μ= 2780 kJ/kg, traveling at a velocity of 56.0 m/s at a height of 3.50 m. First draw a sketch of your system

Answer 1

Answer:

Total energy E of water vapor is 6954005.8 J

Explanation:

given data:

mass = 2.50 kg

specific internal energy μ = 2780 kJ/kg = 2780 ×10³ J/kg

velocity of water vapor = 56 m/s

height h or z = 3.50 m

we know that total energy is given as

total energy E = mμ + $\frac{1}{2}$mv²  + mgh

                        = m(μ +$\frac{1}{2}$v² +gh)

                        = 2.5(2780 ×10³ + $\frac{1}{2}$×56²+9.81×3.50)

                    E = 6954005.8 J