Question

Cesium exists at room temperature as a body centered cubic structure with lattice paramater a=6.06 A. What is the density of cesium?

Answer 1

Answer:

$\rho=1.98 \frac{g}{cm^3}$

Explanation:

Molecular mass of Cesium M=132.9 g/mol

To find density

  $\rho=\dfrac{Z\times M}{a^3N_a}$

Where $N_a=6.022\times 10^{23}$

        a is the lattice parameter,Z=2 for body centered.

$\rho=\dfrac{2\times 132.9}{(6.06\times 10^{-8})^3\times 6.022\times 10^{23}}$

So $\rho=1.98 \frac{g}{cm^3}$