Question

An alpha particle, which has charge 3.20 ✕ 10−19 C, is moved from point A, where the electric potential is 2.40 ✕ 103 J/C, to point B, where the electric potential is 4.95 ✕ 103 J/C. Calculate the work in electron volts done by the electric field on the alpha particle.

Answer 1

Answer:

5100 eV

Explanation:

q = 3.2 x 10^-19 C

Va = 2.4 x 10^3 J/C

Vb = 4.95 x 10^3 J/C

Work done = q (Vb - Va)

W = 3.2 x 10^-19 x (4.95 - 2.4 ) x 10^3 = 8.16 x 10^-16 J

A we know that 1 eV = 1.6 x 10^-19 J

So, W = (8.16 x 10^-16) / (1.6 x 10^-19) = 5100 eV