Question

An indirect contact heat exchanger operating at steady state contains a shell with a single tube through it. The fluid flowing through the tube enters at 1kg/s with and enthalpy of 100kJ/kg. It exits with an enthalpy of 500kJ/kg. The fluid flowing through the shell enters with a mass flow rate of 4kg/s and an enthalpy of 1000kJ/kg. Determine the enthalpy at the exit of the shell.

Answer 1

Answer:900 KJ/kg

Explanation:

Given data

mass flow rate of fluid through tube is=1 kg/s

Initial enthalpy of fluid through tube=100 KJ/kg

Final enthalpy of fluid through tube=500KJ/kg

mass flow rate of fluid through shell is=4 kg/s

Initial enthalpy of fluid through shell=1000 KJ/kg

Final enthalpy of fluid through shell=$h_2$

since heat lost by Shell fluid is equal to heat gain by Tube fluid  

heat lost by Shell fluid=$4\times c\left ( 1000-h_2\right )$

Heat gain by tube Fluid=$1\times c\left ( 500-100\right )$

Equating both heats

$4\times c$$\left ( 1000-h_2\right )$=$1\times c\left ( 500-100\right )$

$h_2$=900 KJ/kg