Answer:
Throat diameter [tex]d_2[/tex]=28.60 mm
Explanation:
Bore diameter [tex]d_1=63mm[/tex] ⇒[tex]A_1=3.09\times 10^{-3} m^2[/tex]
Manometric deflection x=235 mm
Flow rate Q=240 Lt/min⇒ Q=.004[tex]\frac{m^3}{s}[/tex]
Coefficient of discharge [tex]C_d[/tex]=0.8
We know that discharge through venturi meter
[tex]Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}[/tex]
[tex]h=x(\dfrac{S_m}{S_w}-1)[/tex]
[tex]S_m[/tex]=13.6 for Hg and [tex]S_w[/tex]=1 for water.
[tex]h=0.235(\dfrac{13.6}{1}-1)[/tex]
h=2.961 m
Now by putting the all value in
[tex]Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}[/tex]
[tex]0.004=0.8\times \dfrac{3.09\times 10^{-3} A_2\sqrt{2\times 9.81\times 2.961}}{\sqrt{(3.09\times 10^{-3})^2-A_2^2}}[/tex]
[tex]A_2=6.42\times 10^{-4} m^2[/tex]
⇒[tex]d_2[/tex]=28.60 mm
So throat diameter [tex]d_2[/tex]=28.60 mm