A 450 MWt combined cycle plant has a Brayton cycle efficiency of 24% and a Rankine cycle efficiency of 29% with no heat augmentation. Determine the net electric output from the plant.

Respuesta :

Answer:

Output of plant=207.18 MW

Explanation:

Given input energy Q=450 MW

Brayton cycle efficiency[tex]\eta_1=24[/tex]%

Rankine cycle efficiency [tex]\eta_2=29[/tex]%

Combined efficiency for two cycle given as follow

[tex]\eta _b=\eta _1+\eta _2-\eta _1\eta _2[/tex]

[tex]\eta _b=0.24+0.29-0.24\times 0.29[/tex]

[tex]\eta_b=0.4604[/tex]

We know that efficiency [tex]\eta =\dfrac{out\ put}{in\ put}[/tex]

out put of plant=[tex]450\times 0.4604[/tex]

So output of plant=207.18 MW

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