Question

A 2.5-m3 tank contains air at 240 °C and 175 kPa. The air is then heated under constant pressure conditions to a final temperature of 400 °C. Calculate the final volume and the mass of the air inside the tank.

Answer 1

Answer:

m= 2.97 Kg

V₂= 3.28 m³

Explanation:

V₁=2.5 m³         P₁= 175 kPa    T₁=240 ⁰C  = 240+273= 513 K

R=0.287 (characteristic gas constant)

according to ideal gas equation

P₁V₁=mRT₁

$m=\frac{P_1V_1}{RT_1}$

$m=\frac{175\times 2.5 }{0.287\times 513}$

m= 2.97 Kg

T₂=400 °C= 400+273 = 673 K     P₁=P₂= 175 kPa

P₂V₂=mRT₂

$V_2=\frac{mRT_2}{P_2}$

$V_2=\frac{2.97 \times 0.287 \times 673}{175}$

V₂= 3.28 m³