Answer:
[tex]F=55146000 N[/tex]
Explanation:
Given:
Pressure on the building = 170 N/m²
Pressure function P(y) = 170 + 2y
Consider a small height of the building as dy
the small force (dF) exerted on the height dy will be given as
dF = P(y)×(Area of the building face)
or
dF = (170 + 2y)(6565)dy
or
dF = 170×6565×dy + 2y×6565×dy
dF = 1116050dy + 13130ydy
integerating the function for the whole height of 40 m
[tex]\int\limits^{40}_0 {F} = \int _0^{40}\:\left(\:1116050dy\:+\:13130ydy\right)[/tex]
[tex]F = \int _0^{40}1116050dy+\int _0^{40}13130ydy[/tex]
[tex]F=\left[1116050y\right]^{40}_0+13130\left[\frac{y^2}{2}\right]^{40}_0[/tex]
[tex]F=44642000+10504000[/tex]
[tex]F=55146000 N[/tex] ; Total force exerted on the face of the building