Answer:
b) 889 N
Explanation:
We know g = [tex]\frac{10 N}{1 Kg}[/tex]
= 10 m/[tex]s^{2}[/tex]
Now we know, g' = [tex]g\times \frac{R^{2}}{r^{2}}[/tex]
= [tex]10\times \frac{R^{2}}{\frac{3R}{2}^{2}}[/tex]
= 40 / 9
Therefore, pull on the satellite will be = Mg'
= 200 x 40 / 9
= 888.88 N
= 889 N
Pull on the satellite is 889 N