Question

A coil of conducting wire carries a current i. In a time interval of Δt = 0.520 s, the current goes from i1 = 3.20 A to i2 = 1.90 A. The average emf induced in the coil is e m f = 14.0 mV. Assuming the current does not change direction, calculate the coil's inductance (in mH).

Answer 1

Answer:

5.6 mH

Explanation:

i1 = 3.20 A, i2 = 1.90 A, e = 14 mV = 0.014 V,

Let L be the coil's inductance.

$e = -L\times \frac{\Delta i}{\Delta t}$

$0.014 = -L\times \frac{1.90 - 3.20}{0.52}$

L = 0.0056 H

L = 5.6 mH