Answer:
a) 346.22 K
b) 4.49 m³/s
Explanation:
P₁ = P₂ = Pressure in heater = 100 kPa
T₁ = Initial temperature = 300 K
m = Mass flow rate = 6.24 kg/s
Q = Heat transfer rate = 150 kW
Cp = Specific heat at constant pressure of argon = 0.520 kJ/kg K
R = Gas constant of argon = 0.2082 kJ/kg K
a) [tex]Q = mC_p\Delta T\\\Rightarrow 150=6.24\times 0.52\times (T_2-300)\\\Rightarrow \frac{150}{6.24\times 0.52}= T_2-300\\\Rightarrow T_2=346.22 K[/tex]
∴ The argon temperature at the heater exit is 346.22 Kelvin
b) [tex]P_2V_2=mRT_2\\\Rightarrow V_2=\frac{mRT_2}{P_2}\\\Rightarrow V_2=\frac{6.24\times 0.2082\times 346.22}{100}\\\Rightarrow V_2=4.49\ m^3/s[/tex]
∴ Argon volume flow rate at the heater exit 4.49 m³/s