A six-sided number cube is rolled twice.
What is the probability that the first roll is an even number and the second roll is a number greater than 4?

Respuesta :

Answer: 3/6 or 1/2 for even and 2/6 or 1/3 for a number greater than 4.

Step-by-step explanation:

Answer with Step-by-step explanation:

A six-sided number cube is rolled twice.

The sample space is:

(1,1)  (1,2)  (1,3)   (1,4)  (1,5)  (1,6)

(2,1) (2,2) (2,3)  (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3)  (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3)  (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3)  (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3)  (6,4) (6,5) (6,6)

Total outcomes=36

The outcomes with an even number on first roll and number greater than 4 on second roll are in bold letters

Total number of favorable outcomes=3

P(an even number on first roll and number greater than 4 on second roll)

= number of favorable outcomes/total number of outcomes

= 3/36

= 1/12

Hence, probability of an even number on first roll and number greater than 4 on second roll is:

1/12

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