Answer:
9
Step-by-step explanation:
f(x)=2x^2-3x+7
To find the value of the function at f(2), you just replace x with 2:
f(2)=2(2)^2-3(2)+7
f(2)=2(4)-3(2)+7
This is as far as she got. She is doing great so far.
f(2)=8-6+7
f(2)=2+7
f(2)=9
The value of the function at x=2 is 9.
[tex]\large\boxed{\text{f}(2)=9}}[/tex]
In this question, we're solving for the function when x = 2
What this means is that you would plug the number 2 in every "x" value.
When you plug in the 2's, your equation should look like this:
[tex]\text{f}(2)=2(2)^2-3(2)+7[/tex]
Now, you would solve to get your answer.
[tex]\text{f}(2)=2(2)^2-3(2)+7\\\\\text{You would carry over the exponent to the number 2 in the parenthesis,}\\\text{That would be equivalent to 2 * 2, making it 4.}\\\\\text{f}(2)}=2(4)-3(2)+7\\\\\text{f}(2)}=8-3(2)+7\\\\\text{f}(2)}=8-6+7\\\\\text{f}(2)}=9[/tex]
When you're done solving, you should get 9.
This means that f(2) = 9
