Answer:
C program to find the sum of the series( 1/2 + 2/3 + ... + i/i+1)
#include <stdio.h>
double m(int i);//function declaration
//driver function
int main() {
int i;
printf("Enter number of item in the series-\n");//Taking input from user
scanf("%d",&i);
double a= m(i);//Calling function
printf("sum=%lf",a);
return 0;
}
double m(int i)//Defining function
{
double j,k;
double sum=0;
for(j=1;j<i+1;j++)//Loop for the sum
{
k=j+1;
sum=sum+(j/k);
}
return sum;
}
Output:
Enter number of item in the series-5
sum=3.550000
