Answer:
14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.
Explanation:
Animals take in oxygen and breathe out carbon dioxide during cellular respiration. The reaction for the metabolism of the food in the animal body is:
[tex]C_6H_{12}O_6 + O_2 \rightarrow 6CO_2 + 6H_2O + Energy[/tex]
As can be seen from the reaction stoichiometry that:
6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.
Also,
Given :
Mass of carbon dioxide gas = 120 g
Molar mass of carbon dioxide gas = 44 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus, moles of carbon dioxide are:
[tex]moles_{CO_2} = \frac{120 g}{44 g/mol}[/tex]
[tex]moles_{CO_2} = 2.7273 mol[/tex]
As mentioned:
6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.
1 mole of carbon dioxide gas can be produced from 1/6 mole of oxygen gas in the process of metabolism of glucose.
2.7273 mole of carbon dioxide gas can be produced from [tex] \frac{1}{6} \times 2.7273[/tex] moles of oxygen gas in the process of metabolism of glucose.
Thus, moles of oxygen gas needed = 0.4545 moles
Molar mass of oxygen gas = 32 g/mol
The mass of oxygen gas can be find out by using mole formula as:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Mass\ of\ oxygen\ gas = Moles \times Molar mass}[/tex]
[tex]Mass\ of\ oxygen\ gas = 0.4545 \times 32}[/tex]
[tex]Mass\ of\ oxygen\ gas = 14.544 g[/tex]
14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.
Answer:
87.3 g
Explanation:
The cellular respiration can be represented through the following equation.
C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O
We can establish the following relations:
The mass of O₂ that produces 120 g of CO₂ is:
[tex]120gCO_{2}.\frac{1molCO_{2}}{44.01gCO_{2}} .\frac{6molO_{2}}{6molCO_{2}} .\frac{32.00gO_{2}}{1molO_{2}} =87.3gO_{2}[/tex]
