Answer:
The change in length is 3.4 mm.
Explanation:
Given that,
Length = 4 m
Diameter = 2.3 cm
Load = 70 kN
Modulus of elasticity = 200 GPa
We need to calculate the change in length
Using formula of modulus of elasticity
[tex]E=\dfrac{\dfrac{F}{A}}{\dfrac{\Delta l}{l}}[/tex]
[tex]\Delta l=\dfrac{Fl}{AE}[/tex]
Where, F = force
A = area
L = length
E = modulus elasticity
Put the value into the formula
[tex]\Delta l=\dfrac{70\times10^{3}\times4}{\pi\times(1.15\times10^{-2})^2\times200\times10^{9}}[/tex]
[tex]\Delta l=0.00336\ m[/tex]
[tex]\Delta l=3.4\ mm[/tex]
Hence, The change in length is 3.4 mm.
