Question

the solubility of N2 in water is 0.00090 m when the partial pressure above the liquid is 1.6 atm. At what pressure is the solubility equal to 0.00030m

Answer 1

Answer:

The pressure is 0.53 atm

Explanation:

Given that,

Solubility C₁ = 0.00090 m

Solubility C₂ = 0.00030 m

Pressure P₁ = 1.6 atm

We need to calculate the pressure

Solubility directly proportional to partial pressure,

$C_{1}\propto P_{1}$.....(I)

$C_{2}\propto P_{2}$....(II)

From equation (I) and (II)

$\dfrac{C_{1}}{P_{1}}=\dfrac{C_{2}}{P_{2}}$

Where, C = solubility

P = pressure

Put the value into the formula

$\dfrac{0.00090}{1.6}=\dfrac{0.00030}{P_{2}}$

$P_{2}=\dfrac{1.6\times0.00030}{0.00090}$

$P_{2}=0.53\ atm$

Hence, The pressure is 0.53 atm