Answer:
work done=-8.166lb-ft
Explanation:
force = 8 lb spring stretched (x)= 8 in
according to hooks law
F=-kx
k=-[tex]\frac{f}{x}[/tex]
k=-[tex]\frac{8}{8}[/tex]
k=-1 lb/in
work done=[tex]\int_{0}^{14}kx\ dx[/tex]
work done=[tex](-1)\left [\frac{x^2}{2} \right ]^{14} _{0}[/tex]
work done=-98lb-in
1 ft =12 in
work done=[tex]\frac{-98}{12}[/tex]
=-8.166lb-ft
