Question

A rectangular bar has a depth of d = 7 cm and a height of h = 3 cm . The bar is subjected to an axial load P = 400 N . What is the magnitude of the shear force on a plane at an angle θ = 50 ∘

Answer 1

Answer:

SHEAR FORCE = 257.11 N

Explanation:

given data:

depth d = 7 cm

height h = 3 cm

P = 400 N

Area of cross section normal to P = 30*70 = 2100 mm2

Area of cross section (inclined portion) = A'

$sin\theta =\frac{A}{A^{'}}$

$A^{'}= \frac{A}{sin\theta}$

$A^{'}= \frac{2100}{sin50}$

A' =2741.35 mm2

Taking summation of vertical force

$V-Pcos\theta = 0$

v = 400*cos50° = 257.11 N

Average shear force = $\frac{v}{A'}$

Average shear force = $\frac{257.11}{2741.35} = 0.093 MPa$