Question

A toroid of mean radius 26 cm and circular cross section of radius 1.9 cm is wound with a superconducting wire of length 1000 m that carries a current of 410 A. (a) What is the number of turns on the coil?

Answer 1

Answer:

8377 turns

Explanation:

Given:

Mean radius of toroid = 26 cm

Circular cross-section radius, r = 1.9 cm = 0.019

Length of the wire, l = 1000 m

The number of turns (n) on the coil is given by  

$n = \frac{l}{s}$

where,

l is the length of the wire

s is the circumference of the circular wire

⇒$n = \frac{1000}{2\pi r}$

or

$n = \frac{1000}{2\pi \times 0.019}$

or

n = 8376.57 or 8377 turns

hence, the number of turns on the coils is 8377

Answer 2

The number of turns of the coil is determined as 8377 turns.

Number of turns

The number of turns of the superconducting wire is calculated as follows;

n = L/2πr

where;

• L is the length of superconducting wire  = 1000 m
• r is the radius of the circular cross section = 1.9 cm = 0.019 m

Substitute the given parameters and solve for the number of turns of the coil,

n = 1000/(2π x 0.019)

n = 8377 turns

Thus, the number of turns of the coil is determined as 8377 turns.

Learn more about number of turns here: https://brainly.com/question/25886292