Answer:
The current in wire 3 is 0.25 A.
Explanation:
It is given that, three wires meet at a junction.
Current in wire 1, I₁ = 0.4 A
Current in wire 2, I₂ = -0.65 A (out of the junction)
We need to find the magnitude of the current in wire 3 (I₃). Applying Kirchhoff's current law which states that the sum of current in the circuit at a junction is equal to zero.
[tex]I_1+I_2+I_3=0[/tex]
[tex]I_3=-(I_2+I_1)[/tex]
[tex]I_3=-(-0.65+0.4)\ A[/tex]
I₃ = 0.25 A
So, the current in wire 3 is 0.25 A. Hence, this is the required solution.