Question

Two long parallel wires each carry a current of 5.0 A directed to the east. The two wires are separated by 8.0 cm. What is the magnitude of the magnetic field at a point that is 5.0 cm from each of the wires

Answer 1

Answer:

24μT

Explanation:

According to the question the horizontzal component of the field at P are equal and opposite therefore, it will get cancelled.

And vertical components will be added

So, net magnetic field will be $B_{net}$

$B_{net}$= 2Bsinθ

$B=\frac{\mu _{0}I}{2\pi\times5\times10^{-2}}=\frac{2\times10^{-7}\times5}{5\times10^{-2}}$

$B=2\times10^{-5}T$

therefore, $B_{net}$=$2\times2\times10^{-5}\times [\tex][tex]\frac{3}{5}$            ( sinθ=3/5)

on calculating we get $B_{net}$= 24μT