Question

Which of the following has the greatest number of particles? Which of the following has the greatest number of particles? 22.990 g of Na 1 mole of Na 9.012 g of Be 1 mole of Be All are the same.

Answer 1

Answer: All the given options have the same number of particles.

Explanation:

For the given options:

• Option 1: 22.990 g of Na

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of atoms.

If, 22.99 g of sodium metal contains $6.022\times 10^{23}$ number of atoms.

So, 22.990 g of sodium metal will contain $\frac{6.022\times 10^{23}}{22.99}\times 22.990=6.022\times 10^{23}$ number of atoms.

Number of particles = $6.022\times 10^{23}$

• Option 2:  1 mole of Na

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of atoms.

So, 1 mole of sodium element will also contain $6.022\times 10^{23}$ number of atoms.

Number of particles = $6.022\times 10^{23}$

• Option 3:  9.012 g of Be

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of atoms.

If, 9.01 g of beryllium metal contains $6.022\times 10^{23}$ number of atoms.

So, 9.012 g of beryllium metal will contain $\frac{6.022\times 10^{23}}{9.01}\times 9.012=6.022\times 10^{23}$ number of atoms.

Number of particles = $6.022\times 10^{23}$

• Option 4:  1 mole of Be

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of atoms.

So, 1 mole of beryllium element will also contain $6.022\times 10^{23}$ number of atoms.

Number of particles = $6.022\times 10^{23}$

Hence, all the options have same number of particles which is $6.022\times 10^{23}$